Y=-0.08x^2+1.6x+10

Solution for Y=-0.08x^2+1.6x+10 equation:

=-0.08Y^2+1.6Y+10

We move all terms to the left:

-(-0.08Y^2+1.6Y+10)=0

We get rid of parentheses

0.08Y^2-1.6Y-10=0

a = 0.08; b = -1.6; c = -10;
Δ = b2-4ac
Δ = -1.62-4·0.08·(-10)
Δ = 5.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.6)-\sqrt{5.76}}{2*0.08}=\frac{1.6-\sqrt{5.76}}{0.16}
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.6)+\sqrt{5.76}}{2*0.08}=\frac{1.6+\sqrt{5.76}}{0.16}
$